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Grade 11Trigonometry

Evaluate: lim [sin(2x)/x] ; where [] is the x->0 greatest integer function

Profile image of Aryan Suthar
8 Years agoGrade 11
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1 Answer

Profile image of Arun
8 Years ago
 
Dear Aryan
It is a 0/0 form hence using L'hospital rule
 
lim x->0 2 [cos2x /1]
Now
Cos 2x value will always be less than 1 as x is not exactly equal to 0.
Hence
Its GIF will be 0.
 
Now limit will be 
lim x->0 (0/1) 
Hence answer will be 0.
 
Regards
Arun (askIITians forum expert)

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