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x²+2xy-4y²=0 find the acute angle between the pairs of lines.

x²+2xy-4y²=0 find the acute angle between the pairs of lines. 

Grade:11

1 Answers

Aditya Gupta
2081 Points
4 years ago
hello smruti, we know that the acute angle b/w the pairs of lines represented by ax^2+by^2+2hxy+2gx+2fy+c= 0 is given by:
theta= arctan(|2√(h2 – ab)/(a + b)|)
here, h= 1, a= 1 and b= – 4.
so, theta= arctan(|2√(1+4)/(1 – 4)|)
= arctan(2√5/3)= 56 deg approx
kindly approve :)

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