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`        x²+2xy-4y²=0 find the acute angle between the pairs of lines. `
3 months ago

1819 Points
```							hello smruti, we know that the acute angle b/w the pairs of lines represented by ax^2+by^2+2hxy+2gx+2fy+c= 0 is given by:theta= arctan(|2√(h2 – ab)/(a + b)|)here, h= 1, a= 1 and b= – 4.so, theta= arctan(|2√(1+4)/(1 – 4)|)= arctan(2√5/3)= 56 deg approxkindly approve :)
```
3 months ago
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### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions