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Grade: 11
        
What point on x-axis is equidistant from (7,  6) and (-3, 4).
 
 
5 days ago

Answers : (1)

Aman kumar
15 Points
							
Let  P(x,0) be a point on x-axis which is equidistant from the given points.
So from distance formulae,
[(x-7)^2+(0-6)^2]^1/2=[(-3-x)^2+(4-0)^2]^1/2
(x-7)^2+(0-6)^2=(-3-x)^2+(4-0)^2
x^2+49-14x+36=9+x^2+6x+16
49+36-9-16=6x+14x
20x=60
x=3
So, the required point is (3,0)
 
5 days ago
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