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What is the equation of the plane that cuts the coordinate axes (a,0,0) (0,b,0) and (0,0,c)

What is the equation of the plane that cuts the coordinate axes (a,0,0) (0,b,0) and (0,0,c)

Grade:12

2 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,
ATQ:3 points in plane are ( a, 0, 0 ), ( 0, b, 0 ) and ( 0, 0, c ).
Let a be the vector from ( a, 0, 0 ) to ( 0, b, 0 ) :
a = = so x/a +y/b +z/c =1 is the reqd equation of the plane. [Ans]
=>bc(x-a)+acy+abz=0
=0. =0=>n.
General eqn of plane:
Now finding the normal between a and b=n=a x b =bc i+ ac j+ ab k
= b =
similarly let b be vector from ( a, 0, 0 ) to ( 0, 0, c ) :
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Vikas TU
14149 Points
6 years ago
Dear Student,
ATQ:3 points in plane are ( a, 0, 0 ), ( 0, b, 0 ) and ( 0, 0, c ).
Let a be the vector from ( a, 0, 0 ) to ( 0, b, 0 ) :
similarly let b be vector from ( a, 0, 0 ) to ( 0, 0, c ) :
Now finding the normal between a and b=n=a x b =bc i+ ac j+ ab k
General eqn of plane:
=>bc(x-a)+acy+abz=0
so x/a +y/b +z/c =1 is the reqd equation of the plane. [Ans]
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
 

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