Three vertices of triangle ABC are (3,2,-1)B(-1,-1,-1) and C(1,5,5).If the internal bisector of angle BAC meets the opposite side BC at D,then find the co ordinates of D..

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Arun · Answer

Dear student Find length of three sides i.e. AB, BC, CA As we know angle bisector divides the opposite sode in the coreesponding ratio of other sides hence you have ratio, now you can find the cordinates of point which internal bisects the given side

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Three vertices of triangle ABC are (3,2,-1)B(-1,-1,-1) and C(1,5,5).If the internal bisector of angle BAC meets the opposite side BC at D,then find the co ordinates of D..

Three vertices of triangle ABC are (3,2,-1)B(-1,-1,-1) and C(1,5,5).If the internal bisector of angle BAC meets the opposite side BC at D,then find the co ordinates of D..

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Three vertices of triangle ABC are (3,2,-1)B(-1,-1,-1) and C(1,5,5).If the internal bisector of angle BAC meets the opposite side BC at D,then find the co ordinates of D..

Three vertices of triangle ABC are (3,2,-1)B(-1,-1,-1) and C(1,5,5).If the internal bisector of angle BAC meets the opposite side BC at D,then find the co ordinates of D..

1 Answers

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Other Related Questions on Analytical Geometry

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