Three normals are drawn from P(α+β) to y 2 =4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to

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Nalam mohan · Answer

The equation passing through ( , ) is m^3+2m-m - =0 m1=a,m2=-b,me=1. m1+me+me=-2 i.e a-b+1=-2 m1.m2.m3= i.e -a.b= m1m2+meme+m3m1=- i.e -ab-b+a=- -3= + =3

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Three normals are drawn from P(α+β) to y 2 =4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to

Three normals are drawn from P(α+β) to y²=4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to

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Three normals are drawn from P(α+β) to y 2 =4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to

Three normals are drawn from P(α+β) to y2=4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to

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Three normals are drawn from P(α+β) to y²=4x and their equations are y=ax, y+bx=3 & y=x-3, then α+β is equal to