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The value of K such that the straight line (2x + 3y + 4) + K(6x - y +12) = 0 is parallel to y-axis is The value of K such that the straight line (2x + 3y + 4) + K(6x - y +12) = 0 is parallel to y-axis is
Equation of y axisX = 0Hence slope of line = infinity = 1/0Now slope of other kine also should be infinity if they both are parallel.HenceSlope of other line,(-2 -6k)/(3-k) = 1/03 - k = 0Hence k = 3
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