The tangent from the point (2√2,1) to the hyperbolax^2/25-y^2/16=1 include an angle equal to

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sai nath reddy · Answer

we know eqn of tangent is C1=0 then we will get a tangent and to find angle homozenise the tangent with curve we will get where the tangent meets the curve and differentiate the curve and put the point will get slope then find the line …....then using tan(tita1 – tita2) we will got the correct answer its dam sure

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The tangent from the point (2√2,1) to the hyperbolax^2/25-y^2/16=1 include an angle equal to

The tangent from the point (2√2,1) to the hyperbolax^2/25-y^2/16=1 include an angle equal to

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