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The sum of the distance of a point P from two perpendicular lines in a plane is 1, then the locus of P

Shubh Singhal , 10 Years ago
Grade 12th pass
anser 1 Answers
Y RAJYALAKSHMI

Last Activity: 10 Years ago

Let the perpendiculars lines be the x – axis and y – axis.  The sum of the distances from the the point P (x, y) is 1. ie.
|x| + |y| = 1  – this is the locus of the point P which would be the rhombus whose sides are 
x + y = 1; –x + y = 1; x – y = 1; –x – y = 1
If the perpendicular lines are other than co-ordinate axes, then we can get the same solution by using the transformation of the axes concept.
 
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