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Dear student
Solution: Applying Pythagoras Theorem,
we get, (a+2d)2=a2+(a+d)2
=> a2+4d2+4ad=a2+a2+d2+2ad
=> 3d2+2ad-a2=0
=> (d+a)(3d-a)=0
neglecting (d+a)=0, by solving for (3d-a)=0, we get a:d=3:1
Regards
Arun (askIITians forum expert)
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