The shortest distance of the line x-y-2=0 from the curve y = x 2 + 3x + 2 is

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Anshul · Answer

Differentiate eqn of curve to get Dy/dx =2x +3Let Dy / dx = 1 (perpendicular to slope of given line)Now eqn is 1=2x +3X =-1 Put in eqn of curve Y = 0Now we know pt and line both so find dist.Answer is 3/√2

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The shortest distance of the line x-y-2=0 from the curve y = x 2 + 3x + 2 is

The shortest distance of the line x-y-2=0 from the curve y = x² + 3x + 2 is

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The shortest distance of the line x-y-2=0 from the curve y = x 2 + 3x + 2 is

The shortest distance of the line x-y-2=0 from the curve y = x2 + 3x + 2 is

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The shortest distance of the line x-y-2=0 from the curve y = x² + 3x + 2 is