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The locus of the orthocentre of the triangle formed by the lines (1 + p)x – qy + q(1+q) = 0and y=0 where p is not equal to q is a hyperbola a parabola an ellipse a straight line

The locus of the orthocentre of the triangle formed by the lines (1 + p)x – qy + q(1+q) = 0and y=0 where p is not equal to q is
 
  1. a hyperbola 
  2. a parabola
  3. an ellipse
  4. a straight line
 

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
let the orthocentre be H(h,k)
after plotting the line, points on x and y axis are:

-q(q +1)/2(p+1),0                 and   0,q+1   respectively.

Hence the bisector eqn. for sides x = 0  and y = 0  are ----------->

x = -q(q +1)/2(p + 1)     and   y = (q +1)/2

there fore pints of intesection is h,k that is x,y
equating and dividing them we get,

h/k  =  -q/(p+1)
or
y = (-(p+1)/q)x

or  y = mx
which is a straight line.

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