the locus of foot of the perpendicular drawn from

Question

the locus of foot of the perpendicular drawn from the origin to a variable line passing through a fixed point is circle whose diameter is ? Ans is [square root of 13 ] HOW.???

Arun · Accepted Answer

Dear student you have not define the fixed point. I am assuming it as (a, b) Let the line passing through (a,b) be, y= mx-am+b, ........(i) Now a line perpendicular to this passing through origin is, y=-x/m .......(ii) let the feet of the perpendicular be (h,k) From (i) k= mh-am+b .......(iii) From (ii) m= -h/k, Replacing this in (iii) k= (-h/k)*h + a(h/k) +b, hence, k2=-h2+ah+bk, So h2+k2= ah+bk, Hence the locus is x2+y2= ax+by

Analytical Geometry> the locus of foot of the perpendicular dr...

the locus of foot of the perpendicular drawn from the origin to a variable line passing through a fixed point is circle whose diameter is ?

Ans is [square root of 13 ] HOW.???

sreya r , 7 Years ago

Arun

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Analytical Geometry> the locus of foot of the perpendicular dr...

the locus of foot of the perpendicular drawn from the origin to a variable line passing through a fixed point is circle whose diameter is ? Ans is [square root of 13 ] HOW.???

sreya r , 7 Years ago

Arun

LIVE ONLINE CLASSES

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