the inclintion of a straight line is150 degree;if the perpendicular distance of the line from the origin is 10 unit,find the equation of the straight line.

Question

Akshay · Answer

y=mX+c, m=tan(150)=-tan(30)=-1/rt(3), put(0,0) point, |0-0-c|/(rt(1+m 2 )=10, c=+/-10rt(10)/3

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the inclintion of a straight line is150 degree;if the perpendicular distance of the line from the origin is 10 unit,find the equation of the straight line.

the inclintion of a straight line is150 degree;if the perpendicular distance of the line from the origin is 10 unit,find the equation of the straight line.

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