The incenter of the triangle formed by the axes and the line x/a +y/b =1 is?

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Arun · Answer

Dear student Vertices will be (0, 0) (a, 0) , (0, b) Now the incentre will be: ((Px1 + Qx2 +Rx3)/(P+Q+R) ,(Py1 + Qy2 +Ry3)/(P+Q+R)) where P, Q and R are the dstances between the coordinates of the tringles opposite to vertices of triangle ABC.

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The incenter of the triangle formed by the axes and the line x/a +y/b =1 is?

The incenter of the triangle formed by the axes and the line x/a +y/b =1 is?

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