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The incenter of the triangle formed by the axes and the line x/a +y/b =1 is?
Dear student Vertices will be (0, 0) (a, 0) , (0, b)Now the incentre will be:((Px1 + Qx2 +Rx3)/(P+Q+R) ,(Py1 + Qy2 +Ry3)/(P+Q+R)) where P, Q and R are the dstances between the coordinates of the tringles opposite to vertices of triangle ABC.
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