Vikas TU
Last Activity: 8 Years ago
let at h distance from base it is cut then,
Volume of this cut cone = > (1/3)*pi*r^2(24-h) cm^3 = V
Volume of original cone = > V’ = (1/3) * pi* R^2 * 24
dividing the V and V’ we get,
V/V’ = (r/R)^2 * (24-h)/24 = > 1/64
Now from similar triangles in small and cutted cone we get the relation inheight and radii are:
r/R = (24 – h)/24
[(24 – h)/24]^3 = 1/64
(24-h)/24 = ¼
24 – h = 6
h = 18 cm.