The extremities of the base of an isosceles triangle ABC are the points A(2,0) and b (0,1).if the equation of the side ac is x=2 then the slope of the side bc is???

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arunkumaran · Answer

equation of side ac is x=2, so the point c has coordinates (2,k) and also distance between points a and c is equal to points b and c(since isosceles),so (k=5/2) and usng slope formula slope of bc is 3/4

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The extremities of the base of an isosceles triangle ABC are the points A(2,0) and b (0,1).if the equation of the side ac is x=2 then the slope of the side bc is???

The extremities of the base of an isosceles triangle ABC are the points A(2,0) and b (0,1).if the equation of the side ac is x=2 then the slope of the side bc is???

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The extremities of the base of an isosceles triangle ABC are the points A(2,0) and b (0,1).if the equation of the side ac is x=2 then the slope of the side bc is???

The extremities of the base of an isosceles triangle ABC are the points A(2,0) and b (0,1).if the equation of the side ac is x=2 then the slope of the side bc is???

1 Answers

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Other Related Questions on Analytical Geometry

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