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Grade: 12
        
The equation of the parabola to which the line m^2(y-10)-mx-1=0 is a tangent for any real value of m
one month ago

Answers : (2)

Arun
23520 Points
							
Dear student
 
Question is incomplete. Please check and repost the question. You can also attach an image. Na dif possible please post options too. as they are required.
 
one month ago
Aditya Gupta
1819 Points
							
hello mounika. fromwe know that am^2) for all values of m.2am, at (= 4ay  is a tagnent to the parabola x^2y = mx - am^2 ….... (1)
m^2(y-10)-mx-1=0 can be written as (y-10)= x/m+1/m^2
or Y= nx – ( – 1)n^2 .........(2), where n= 1/m (and hence n can also be any real since m can vary over the reals) and Y= y – 10
on comparing (2) and (1) we have a= – 1
so, the corresponding parabola would be x^2 = 4aY
substituting values
x^2 = 4*( – 1)(y – 10)
or x^2 + 4(y – 10) = 0
kindly approve :))
one month ago
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