The equation of the line passing through (2,3)and perpendicular to the line joining (-5,6)and (-6,5)?

Question

Arun · Answer

Dear student m for a perpendicular line = 5 – 6 / -6 +5 = 1 hence slope for required line wll be = – 1 hence line L = y – 3 = – 1(x – 2) y – 3 = – x + 2 x + y = 5

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The equation of the line passing through (2,3)and perpendicular to the line joining (-5,6)and (-6,5)?

The equation of the line passing through (2,3)and perpendicular to the line joining (-5,6)and (-6,5)?

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