Grade 10Analytical Geometry
The equation of locus of the point (asecp+btanp,atanp+bsecp)
1 Answer
Arun
Dear student
x = a secp + b tanp
y = a tanp + b secp
x² = a² sec²p + b² tan²p + 2ab secp tanp
y² = a² tan²p + b² sec²p + 2ab secp tanp
Now
x² - y² = a²(sec²p - tan²p) + b²( tan²p - sec²p)
x² - y² = a² - b²
Hence this will be the equation.
Which reperesere hyperbola.
Regards
Arun (askIITians forum expert)
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