MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
The centriod of equilateral triangle is an origin and one of the side equation x+y=2. Find equations of other sides. 
2 months ago

Answers : (1)

Vikas TU
9225 Points
							
Dear student 
The perpendicular bisector of the given side is y = x
Then intersection of the bisector and the line x+y = 2 is at (1,1) 
The distance from the centroid to the vertex on y = x is 2x the distance from the origin to the line --> the vertex is at (-2,-2)
The slope of x+y=2 is -1 --> the tangent of the angle with the x-axis = 135 degs
The angles of the 2 other sides with the x-axis are 75 degs and 195 degs. 
The slope of a line = the tangent of the angle with the x-axis.
Tan(195)=2-root3=slope
y + 2 = (2 - sqrt(3))*(x + 2) eqn of 1 line 
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details