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The centriod of equilateral triangle is an origin and one of the side equation x+y=2. Find equations of other sides.

The centriod of equilateral triangle is an origin and one of the side equation x+y=2. Find equations of other sides. 

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
Dear student 
The perpendicular bisector of the given side is y = x
Then intersection of the bisector and the line x+y = 2 is at (1,1) 
The distance from the centroid to the vertex on y = x is 2x the distance from the origin to the line --> the vertex is at (-2,-2)
The slope of x+y=2 is -1 --> the tangent of the angle with the x-axis = 135 degs
The angles of the 2 other sides with the x-axis are 75 degs and 195 degs. 
The slope of a line = the tangent of the angle with the x-axis.
Tan(195)=2-root3=slope
y + 2 = (2 - sqrt(3))*(x + 2) eqn of 1 line 

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