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The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a2. The locus of the third vertex is
Let the third vertex of a triangle be C (h,k).Other two vertices are A and B.that is let, (a,b1) and (a, b1+a) respectively.Area is given therfore,a^2 = det( | a b1 1| |a b1+a 1| |h k 1| )................(1)Then apply the distance formulae using coordinates of the triangle ABC with a as a constant distance b/w them. From there U would get again some other eqns.
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