The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a2. The locus of the third vertex is

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Vikas TU · Answer

Let the third vertex of a triangle be C (h,k). Other two vertices are A and B. that is let, (a,b1) and (a, b1+a) respectively. Area is given therfore, a^2 = det( | a b1 1| |a b1+a 1| |h k 1| )................(1) Then apply the distance formulae using coordinates of the triangle ABC with a as a constant distance b/w them. From there U would get again some other eqns.

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The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a2. The locus of the third vertex is

The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a2. The locus of the third vertex is

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