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The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a 2. The locus of the third vertex is (x+a)(x-3a)=0 (x-a)(x+3a)=0 (x-a)(x-3a)=0 (x-a)(x-2a)=0

The base of the triangle lies along the line x=a and is of length a. The area of the triangle is a2.  The locus of the third vertex is 
 
(x+a)(x-3a)=0
(x-a)(x+3a)=0
(x-a)(x-3a)=0
(x-a)(x-2a)=0

Grade:11

1 Answers

Vikas TU
14149 Points
5 years ago
Hello user,
Simalr question has been asked .
plz check this askiitian link:
 
http://www.askiitians.com/forums/Analytical-Geometry/the-base-of-the-triangle-lies-along-the-line-x-a-a_154398.htm

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