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The base of a triangle is axis of x and its other 2 sides are given by the equations : y = (1+α)x/α + (1+α) and y = (1+β)x/β + (1+β). Prove that the locus of its orthocentre is the line x+y = 0. Please provide step-by-step solution.

The base of a triangle is axis of x and its other 2 sides are given by the equations :

y = (1+α)x/α + (1+α) and y = (1+β)x/β + (1+β).

Prove that the locus of its orthocentre is the line x+y = 0. Please provide step-by-step solution.

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
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