Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

the area of the triangle whose vertices are the incentre,centroid, and circumcentre of a triangle with sides 14,50,48 is??

the area of the triangle whose vertices are the incentre,centroid, and circumcentre of a triangle with sides 14,50,48 is??

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
Dear Student,
we know, A=1/4 sqrt((a + b - c) (a - b + c) (-a + b + c) (a + b + c))
Substituting a=14, b=50, c=48:
A=1/4 sqrt((14 + 50 - 48) (14 - 50 + 48) (-14 + 50 + 48) (14 + 50 + 48))
=>A=(sqrt((14 + 50 - 48) (14 - 50 + 48) (-14 + 50 + 48) 112))/(4)
=>A=(sqrt((14 + 50 - 48) (14 - 50 + 48) 84×112))/(4)
14 - 50 + 48=12:
=>A=(sqrt((14 + 50 - 48) 12×84×112))/(4)
14 + 50 - 48=16:
=>A=(sqrt(16×12×84×112))/(4)16×12 =192
=>sqrt(1806336) = sqrt(2^12×21^2) = 2^6×21:
=>A=(2^6×21)/4
=>A=((2×4)^2 21)/4
A=16×21
16×21 = 336 (ans)
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free