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The angle between the tangents drawn from the point (1,2) to the ellipse 3x2+2y2=5 is A) tan^-1(12/5)B) tan^-1(6/√5)C) tan^-1(12/√5)D) tan^-1(6/5)

The angle between the tangents drawn from the point (1,2) to the ellipse 3x2+2y2=5 is A) tan^-1(12/5)B) tan^-1(6/√5)C) tan^-1(12/√5)D) tan^-1(6/5)

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1 Answers

Arun
25763 Points
3 years ago
Dear student
 
first find out the slope of both the tangents and then find angle between them.
 
I am getting my answer as tan –1 (12/ \small \sqrt5)
 
 
Regards
Arun (askIITians forum expert)

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