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`        Suppose that the normals drawn at three different points on the parabola y^2=4ax pass through the point (h, k),. Show that h›2,... Conic sections`
3 years ago

```							equation of normal to parabola y2=4x is y=mx-2m-m3 it passes through  ( h,k)  hence ,k =mh -2m-m3m3+(2-h)m +k=0let m1 , m2 ,m3 be roots of the equation , now we will use properties cubic  equations,then m1+m2+m3= -coefficient of m2/ coefficient of m3 =0 …........(as there is no m2 term)m1m2+m2m3+m3m1=coefficient of m/ coefficient of m3 = 2-hm1m2m3 = -constant term/ coefficient of m3  = -k  ,hence all the values m1 ,m2 , m3 cant be zerom12+m22+m32 >0i.e. (m1+m2+m3)2 -2(m1m2+m2m3+m3m1)>0i.e. (  0  )2 -2 (2-h)>0i.e -2(2-h)>0i.e. h-2>0  => h>2 …..........................result will be same for y2=4axplease approve if you are satisfied :)
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3 years ago
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