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`        Question number 9Ans is Before rotation (4,4)(2,-2) andAfter rotation.  (3-root2, 1+2root2),                     (3+root2,1-2root2)..................... `
3 months ago

```							easily solve both eqns together to find intersection point P(3, 1).given L2= 3x= y+8 with slope m1= 3after rotation it becomes L2’ which passes through P. its slope will become (m1+m2)/(1 – m1*m2), where m1 is slope of L2 and m2= tanpi/4= 1. so (m1+m2)/(1 – m1*m2)= 4/-2= – 2so, eqn of line is L2’: y – 1= – 2(x – 3)or y+2x= 7any point on above line is of the form A or B(c, 7 – 2c).so, PA= OPPA^2= OP^2(c – 3)^2+(7 – 2c – 1)^2= 3^2+1^2(c – 3)^2+4(c – 3)^2= 10or (c – 3)^2= 2or c= 3 ± root2so that 7 – 2c= 1 ∓ 2root2kindly approve :)
```
3 months ago
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