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`        Question 7.Ans is  x-y=0........................... `
3 months ago

```							let coordinates of A be (a, 0) and B be (0, b). drop a perpendicular from D to the x axis and let it meet at P. let O be the origin.then, angle AOB= angle DPA= 90 deg,AB= DA (ABCD is square)angle OBA= angle PAD ( because OAB+OBA= 90 and OAB+90+PAD= 180).by AAS, triangles AOB and DPA are congruent. so, PD= OA= aand PA= OB= bso coordinates of D are (OA+AP, PD)= (a+b, a)now, mid point of B and D is the centre of square.by mid point theorem,M= [(0+a+b)/2, (b+a)/2]M= [(b+a)/2, (b+a)/2]= (h, k) sayso, h= (b+a)/2 and k= (b+a)/2or h=kreplace h and k by x and yx= yx – y= 0kindly approve  :=)
```
3 months ago
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