question 5

Ans is 7x-y=6 or x+7y=8

In this question i find point c(7,-7) and AC=CB=CP=10. but unable to find point B and P.

Please do last some step.

ok so we obviously know that B and P both exist on line 3x= 4y+49. so their coordinates are of the form (4p+15, 3p – 1). note that this is the parametric way of choosing coordinates on a line. if you are unfamiliar with it you can simply assume the point of the form [(4k+49)/3, k].

now, apply distance formula

CB^2 or CP^2= 10^2

(4p+15 – 7)^2 + (3p – 1 – ( – 7))^2= 100

solving, you get p= 0, – 4

hence points B or P are (15, – 1) or ( – 1, – 13).