Quadrilateral ABCD has ∠BDA = ∠CDB = 50°, ∠DAC = 20° and ∠CAB = 80°. Find angles ∠BCA and ∠DBC.

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In Triangle BOC
► Angle B + angle O + angle C=180 Deg
60 deg +angle O +30 Deg=180 Deg
angle O=180 Deg – 90 Deg
=90 Deg
60Deg + angle O + 30 Deg=180Deg
angle O=180 Deg – 90 Deg
=90 Deg
so angle BOC= 90 Deg = angle AOB = angle AOD

In Triangle AOD

angle A+angleO+angleD=180Deg
angle A+90Deg+60Deg=180Deg
angle A=(180-150)=30 Deg

So angle DAC=30 Deg

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Toshika Choyal