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Prove that the locus of the center of a circle , which intercepts a cord of given length 2a on the axis of x and passes through a given point on the axis of y distant b from the origin , is the curve x^2-2yb+b^2=a^2
one year ago

Answers : (1)

Arun
23357 Points
							
 
We know length of intercept made by circle on X axis is 2√(-C )= 2A 
AND.  Length of intercept made by circle on y axis is 2 √(F 2 --c)=b 
Just do the squaring and add them you will get the same equation
one year ago
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