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Prove that the eccentric angles of the extremities of latus recta of the ellipse x^2/a^2+y^2/b^2=1(a>b) is tan-1(+-b/ae)
please answer quickly

supraja venkatraman , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear student
 
Let a cos @ = ae
b sin @ = ± b^2/a
 
b/a tan@ = ± b^2 /a^2 e
 
hence tan@ = ± b/ ae
 
hope it helps
 
Regards
Arun
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