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prove that four straight lines represented by the equation 12x2 +7xy -12y2=0 and 12x2 +7xy -12y2 -x +7y -10 form a square
Hello Student,12x2+7xy -12y2=012x2+7xy -12y2-x +7y -10with first x=(-7y +- yroot(49+144*4))/24you will get 2 lines from herewith second do the same thingx=(-7y+1 +- root((7y-1)^2 – 4*(12)(-12y^2+7y-10)))after solving you will find that under root part is actually a perfect squareNow you got 4 eq. youEvaluate yourself.Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
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