Vikas TU
Last Activity: 7 Years ago
Origin lies on y=3x+2.
Taking out x from condition utilizing x = y-2/3 from first condition and utilizing it in x^2+2xy+3y^2+4x+8y-11=0
condition you will get is
34y2+74y-167=0
arrangements are y = 47 and y=121
we realize that x=y-2/3
on substituting , we get
so purposes of crossing point are (15, 47) and (119/3 , 121)
as should be obvious they lie in various quadrants and source is between them at stake y=3x+2
so point is tan-1(0.942)