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Please give answer urgent. Thanks I attached question in attachment.
A=3,2 O=5,6 m=2 so eq=2x-y-4=0 so perpendicular line eq -y-2x=k sub 5,6 in above equation then k=-17 so required equatiion =2x+y-17=0
given A=3,2 and let intersection O=5,6 and B=x,y . as AO is perpendicular to OB. product of slopes is -1. we get 2(6-y/5-x)=-1. eq is x+2y-17=0
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