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Please give answer urgent. Thanks I attached question in attachment.

Please give answer urgent. Thanks I attached question in attachment.

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Grade:11

2 Answers

Venky
53 Points
4 years ago
A=3,2   O=5,6     m=2  so eq=2x-y-4=0  so perpendicular line eq -y-2x=k    sub 5,6 in above equation      then k=-17    so required equatiion =2x+y-17=0
Dharma Teja
33 Points
4 years ago
given A=3,2 and let intersection O=5,6 and B=x,y . as AO is perpendicular to OB. product of slopes is -1. we get 2(6-y/5-x)=-1. eq is x+2y-17=0

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