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`        please answer fast..............slope of two tangent drawn from (3/2, 5) to parabola y^2=6x are???please give solution`
one year ago

```							 Since we know thatSlope =dy/dx              =6x/2yNow substitute the given Co ordinatesX=3/2 Y=5            =6×3/2×5×2              =9/10
```
one year ago
```							y2 = 6x   y2 = 4. 6x/4  y2 = 4.(3/2)xComparing above equation with general equation of parabola y2 = 4ax, we geta = 3/2We know that equation of any tangent to parabola y2 = 4ax isy = mx + a/m , where m is the slope of the tangent.Here, equation of tangent would be y = mx + (3/2)/m   i.e.              y = mx + 3/2m                                     ….(1) It passes through (3/2,5), i.e., (3/2,5) satisfies eq. (1) 5 = 3m/2 + 3/2m   5 = (3/2)(m + 1/m) 10/3 = (m2 + 1)/mSolving above equation, we get3m2 – 10m +3 = 0 (3m – 1)(m – 3) = 0m = 1/3   or   m = 3Thus, the required slopes are 1/3 and 3.
```
one year ago
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