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please answer fast ….........equation of tangent to the parabola y^2=4a(x+a) having slope 1 is ????
please give solution for it.............

Mrunal Sonawane , 6 Years ago
Grade 12
anser 1 Answers
Shiva Rao

Last Activity: 6 Years ago

Slope=dy/dx
           =4a/2y
       1= 4a/2y
        Y=2a
Put in equation of slope 
We get
X=1
Substitute in
 
Y-y1= m(x-x1)
Y-2a=x-1
Y-x=2a-1
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