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Perpendicular distance from origin to the line 3x+4y=15 is?

Hithaishi S R , 6 Years ago
Grade 11
anser 2 Answers
Deepak Kumar Shringi

Last Activity: 6 Years ago

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Ankit kumar jha

Last Activity: 6 Years ago

The perpendicular distance from a point to the line is given by ( |ax1+by1+c| ) /(a^2 +b^2 ) ^(1/2). Put x1 and y1 as 0,0and a=3 b=4 you will  get  the distance. Distance =3
                    

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