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Perpendicular distance from origin to the line 3x+4y=15 is? Perpendicular distance from origin to the line 3x+4y=15 is?
The perpendicular distance from a point to the line is given by ( |ax1+by1+c| ) /(a^2 +b^2 ) ^(1/2). Put x1 and y1 as 0,0and a=3 b=4 you will get the distance. Distance =3
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