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one end of latusrectum of the parabola (x+2)^2 = -4(y+3)........... please give solution....

one end  of latusrectum of the parabola (x+2)^2 = -4(y+3)...........
please give solution....

Grade:12

1 Answers

Arun
25758 Points
3 years ago
 
Dear student
 
here end point of latus rectum = ( ± 2a,  – a ) type
 
a = 1 here
 
x + 2 = ± 2 hence x = 0 or x = – 4
 
y + 3 = – 1 hence y = – 4
 
hence end points are =(0, – 4) and ( – 4, – 4)

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