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Line bx+ay =3 ab cuts coordinate axes at A and B. Centroid of triangle OAB?
Let’s find all the vertexes first of triangle OAB
The given line is bx+ay=3abSince this line cuts the coordinate axiswe will draw it in coordinate axis we get x=3a and y=3bTake them as x1and y1and one point is (0,0) as it lies on originPut it in centroid formx=x1+x2+x3/3 = 3a+0+0/3 = aY=y1+y2+y3/3 = bThe points are (a,b)
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