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Grade 11Analytical Geometry

Let P be the point on the parabola y2=3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

Profile image of Meghana
6 Years agoGrade 11
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1 Answer

Profile image of Aditya Gupta
6 Years ago
hello meghana, note that there is some mistake in the question, as in the last line u have written:
“If S is the focus of the parabola, then S is equal to”
obviously we can easily calculate S by writing y2=3x as y2= 4*(3/4)x so that S= (3/4, 0).
kindly repost the correct ques with a pic attached

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