Let P be the point on the parabola y 2 =3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

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Aditya Gupta · Answer

hello meghana, note that there is some mistake in the question, as in the last line u have written: “ If S is the focus of the parabola, then S is equal to ” obviously we can easily calculate S by writing y 2 =3x as y 2 = 4*(3/4)x so that S= (3/4, 0). kindly repost the correct ques with a pic attached

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Let P be the point on the parabola y 2 =3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

Let P be the point on the parabola y²=3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

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Let P be the point on the parabola y 2 =3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

Let P be the point on the parabola y2=3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to:

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Let P be the point on the parabola y²=3x such that OP make an angle of pi/6 with the x-axis, where O is the origin. A normal is drawn to the parabola at P intersecting the axis of the parabola at Q. If S is the focus of the parabola, then S is equal to: