Riddhish Bhalodia
Last Activity: 9 Years ago
It’s simple
Lets say L1 is y=mx
Then as chords are equal the perpendicular distance from the center of the circle should also be same
center is
(1/2,-3/2)
so we have (by equating the perpendicular distance from center to L1 and L2)

squaring and simplifying we get the quadratic as

whose roots are
m=1,-1/7
so possible values of L1 are
x=y and
x = -7y