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its regarding ellipse and how to find the eccenticity when latus rectum subtends at right angles at the centre of the ellipse

its regarding ellipse and how to find the eccenticity when latus rectum subtends at right angles at the centre of the ellipse

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Grade:12th pass

1 Answers

Khimraj
3007 Points
5 years ago
Just consider your half triangle then tan45° = b²/a(ae) so b²/a² = e. Then 1-e² = e and e² +e-1=0. So e = √5-1/2.Hope it clears. If u have doubts then please clearify. And if u like my answer then please approve answer

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