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its regarding ellipse and how to find the eccenticity when latus rectum subtends at right angles at the centre of the ellipse

anila , 7 Years ago
Grade 12th pass
anser 1 Answers
Khimraj

Last Activity: 7 Years ago

Just consider your half triangle then tan45° = b²/a(ae) so b²/a² = e. Then 1-e² = e and e² +e-1=0. So e = √5-1/2.Hope it clears. If u have doubts then please clearify. And if u like my answer then please approve answer

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