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in expansion of [3^1/7+5^1/49]^4319,THE NUMBER OF TERMS FREE FROM RADICALS IS.....??
The general term in the expansion of[3^1/7+5^1/49]^4319 is nCr (x)^(n-r).a^r=4319Cr(3^1/7)^(4319-r).(5^1/49)^r=4319Cr.3^(4319-r)/7. (5)^r/49=4319Cr (3)^(617-r/7).(5)^r/49This term will be free of radical if r is multiple of 49 .But r<n so value of r may be 49,98,147,.............If we divide 4319 by 49 we get 88 as quotient. It means there will ne 88 term which will be free of radicals.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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