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In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again
at points A1, B1, C1, respectively. If angle ABC = 45° then angle A1B1C1 equals

Vineeth , 10 Years ago
Grade 11
anser 1 Answers
Latika Leekha

Last Activity: 10 Years ago

Hello student,
We are given that ∠ABC = 45°
So, ∠BCH = 45° = ∠BCA1
∠C1CA1 = 45° + 45° = 90°
So, ∠C1B1A1 = 90°
Hence, the required angle ∠A1B1C1 = 90°.

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