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In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again at points A 1 , B 1 , C 1 , respectively. If angle ABC = 45° then angle A 1 B 1 C 1 equals

In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again
at points A1, B1, C1, respectively. If angle ABC = 45° then angle A1B1C1 equals

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Grade:11

1 Answers

Latika Leekha
askIITians Faculty 165 Points
6 years ago
Hello student,
We are given that ∠ABC = 45°
So, ∠BCH = 45° = ∠BCA1
∠C1CA1 = 45° + 45° = 90°
So, ∠C1B1A1 = 90°
Hence, the required angle ∠A1B1C1 = 90°.

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