# In a triangleroot(abc(a+b+c))/area is always greater than of equal to ?less than or equal to

$\\ {\sqrt{abc(a+b+c)} \over \Delta}={\sqrt{4R\Delta2s} \over \Delta} \\=>\sqrt{8Rs \over \Delta } \\=>\sqrt{8R \over r} \geq \sqrt{8*2}=4$