In a triangle ABC, if A(2,-1) and 7x-10y+1=0 and 3x-2y+5=0 are equations of an altitude and an angle bisector respectively drawn from B, then equation of BC is?

First, solve the two equation i.e. - 3x-2y+5 =0and 7x -10y+1=0 to get the point "B" which is intersection point of the two given line. Second, take image of point "A" on BC with respect to either of line i.e. (-64/13 ; -47/13) or (-52/149; -649/149) .Third, now apply two point form of line to get the equation of BC