In a problem involving this step, h/7+5k/c=1 7h-k/5=1 we get 1/5k(1-h/7)=1/7h(1+k/5) -3 how can we get 3 rd eq by the above two equations

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Vikas TU · Answer

Dear Student, ​The question is here incomplete and Non- Understandable. Pls do check the qstn. and Repost it again for the proper clarification. Cheers!! Regards, Vikas (B. Tech. 4 th year Thapar University)

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In a problem involving this step, h/7+5k/c=1 7h-k/5=1 we get 1/5k(1-h/7)=1/7h(1+k/5) -3 how can we get 3 rd eq by the above two equations

In a problem involving this step,
h/7+5k/c=1
7h-k/5=1
we get 1/5k(1-h/7)=1/7h(1+k/5) -3
how can we get 3^rd eq by the above two equations

1 Answers

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In a problem involving this step, h/7+5k/c=1 7h-k/5=1 we get 1/5k(1-h/7)=1/7h(1+k/5) -3 how can we get 3 rd eq by the above two equations

In a problem involving this step, h/7+5k/c=17h-k/5=1we get 1/5k(1-h/7)=1/7h(1+k/5) -3how can we get 3rd eq by the above two equations

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In a problem involving this step,
h/7+5k/c=1
7h-k/5=1
we get 1/5k(1-h/7)=1/7h(1+k/5) -3
how can we get 3^rd eq by the above two equations