find the perpendicular vector to the plane by joining points (1,2,3) and (3,4,5,) also find the mid point (2,3,4,) that lies on the plane now find equation of plane by using there two
Last Activity: 7 Years ago
Arun
Dear student
Normal vector to plane is
(3-1) i + (4-2) j + (5-3) k
= 2i + 2j + 2k
now
equation of plane will be like
2x + 2y + 2 z = d
now it passes through (2,3,4)
hence
4 + 6 + 8 = d
d = 18
hence equation of plane is
x + y + z = 9
Last Activity: 7 Years ago
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